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-7.26x^2+490x-123=0
a = -7.26; b = 490; c = -123;
Δ = b2-4ac
Δ = 4902-4·(-7.26)·(-123)
Δ = 236528.08
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(490)-\sqrt{236528.08}}{2*-7.26}=\frac{-490-\sqrt{236528.08}}{-14.52} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(490)+\sqrt{236528.08}}{2*-7.26}=\frac{-490+\sqrt{236528.08}}{-14.52} $
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